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Practice question

MCQ

Question

What is the excess pressure inside a mercury drop of radius 1.5mm at 20∘C? (Surface tension = 0.4355N/m)

Options

Choose one · Correct answer highlighted

Explanation

Excess pressure: ΔP = 2Sr. S = 0.4355N/m, r = 1.5×10−3m. ΔP = 2×0.43551.5×10−3 = 580.67Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 580 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

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