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Practice question

MCQ

Question

Water flows through a horizontal pipe at a speed of 3m/s with a pressure of 1.5×105Pa. If the speed increases to 6m/s, what is the new pressure? (ρ\=1000kg/m3)

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Explanation

Using Bernoulli’s equation: P1+12ρv12 = P2+12ρv22 (height constant). P1 = 1.5×105Pa, v1 = 3m/s, v2 = 6m/s, ρ = 1000kg/m3. P2 = P1+12ρ(v12−v22) = 1.5×105+12×1000(9−36). P2 = 1.5×105−13500 = 1.365×105Pa.

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