Practice question
Question
Three particles of masses 4kg, 8kg, and 12kg are at (1,0), (3,2), and (0,4) respectively. What is the y-coordinate of their center of mass?
Explanation
Formula: Y = m1y1+m2y2+m3y3m1+m2+m3. Masses: 4,8,12kg; y-coordinates: 0,2,4. Y = (4×0)+(8×2)+(12×4)4+8+12 = 0+16+4824 = 6424 = 2.67m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.67 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.