Practice question
Question
Three particles of masses 2kg, 4kg, and 8kg are at (0,3), (4,0), and (2,5) respectively. What is the y-coordinate of their center of mass?
Explanation
Formula: Y = m1y1+m2y2+m3y3m1+m2+m3. Masses: 2,4,8kg; y-coordinates: 3,0,5. Y = (2×3)+(4×0)+(8×5)2+4+8 = 6+0+4014 = 4614≈3.29m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.29 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.