Practice question

4 sides: r = 3m, 2 diagonals: r = 32m. V = −4Gm23−2Gm232. V = −6.67×10−11×9(43+232). V = −6.003×10−10(1.333+0.471)≈−1.08×10−9J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to -1.1 × 10⁻⁹ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.