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Question

A uniform rod of mass 2kg and length 1m is pivoted at one end. What is its moment of inertia about the pivot?

Options

Choose one · Correct answer highlighted

Explanation

Moment of inertia of a rod about an end: I = 13ML2. M = 2kg, L = 1m. I = 13×2×(1)2 = 23≈0.67kg m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.67 kg m². This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.