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Practice question

MCQ

Question

A steel rod has a length of 1m at 20∘C. What will be its length at 120∘C if the coefficient of linear expansion of steel is 1.2×10−5K−1?

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Explanation

Given: L0 = 1m, T1 = 20∘C, T2 = 120∘C, αl = 1.2×10−5K−1. ΔT = 120−20 = 100∘C. Linear expansion: ΔL = L0αlΔT = 1×1.2×10−5×100 = 1.2×10−3m. New length: L = L0+ΔL = 1+0.0012 = 1.0012m.

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