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Question

A satellite orbits Earth at 17RE from the center. What is its orbital speed? (g\=9.8m/s2,RE\=6.4×106m)

Options

Choose one · Correct answer highlighted

Explanation

v = gRE2r. r = 17RE, v = 9.8×6.4×10617. v = 3.694×106≈1.92×103m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.9 × 10³ m/s. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.