Projectile Motion: Max Height for 16 m/s at 30°

Practice question

Question

A projectile is launched with a speed of 16m/s at an angle of 30∘ to the horizontal. What is its maximum height? (Take g\=10m/s2,sin⁡30∘\=0.5)

Options

Choose one · Correct answer highlighted

12.8 m Correct 10.2 m 15.4 m 14.8 m

Explanation

Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 12.8 m. Hence option A satisfies projectile formulas.

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