Practice question
Question
A hydraulic system applies 180N on a small piston of area 0.012m2. What force is exerted by a large piston of area 0.06m2?
Explanation
Pascal’s law: P = F1A1 = F2A2. F2 = F1×A2A1. F1 = 180N, A1 = 0.012m2, A2 = 0.06m2. F2 = 180×0.060.012 = 180×5 = 900N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 900 N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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