Skip to content

Question

A gas at 37∘C and 3atm occupies 6L. If it is cooled to −13∘C while the volume is reduced to 4L, what is the final pressure?

Options

Choose one · Correct answer highlighted

Explanation

Given: T1 = 37∘C = 310K, P1 = 3atm, V1 = 6L, T2 = −13∘C = 260K, V2 = 4L. Ideal gas law: P1V1T1 = P2V2T2. P2 = P1×V1V2×T2T1 = 3×64×260310. P2 = 3×1.5×0.8387≈3.77atm.