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Question

A gas at 3.5atm and 77∘C occupies 4.5L. If the temperature drops to 27∘C and volume increases to 6L, what is the final pressure?

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Explanation

Given: P1 = 3.5atm, T1 = 77∘C = 350K, V1 = 4.5L, T2 = 27∘C = 300K, V2 = 6L. P1V1T1 = P2V2T2. P2 = P1×V1V2×T2T1 = 3.5×4.56×300350 = 3.5×0.75×0.8571≈2.25atm.

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