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Practice question

MCQ

Question

A force F\=−3i^−4j^N acts at r\=2i^+5j^m. What is the magnitude of the torque about the origin?

Options

Choose one · Correct answer highlighted

Explanation

τ = r×F = |i^j^k^250−3−40| = k^(2×(−4)−5×(−3)) = k^(−8+15) = 7k^Nm. Magnitude = 7Nm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 7 Nm. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

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