Practice question
Question
A brass wire of length 2.0m and cross-sectional area 2×10−6m2 is stretched by a force of 300N. If the Young's modulus of brass is 9×1010N/m2, what is the strain produced?
Explanation
Stress: Stress = FA = 3002×10−6 = 1.5×108N/m2. Young's modulus: Y = StressStrain. Strain: Strain = StressY = 1.5×1089×1010≈1.67×10−3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.67×10−3. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
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