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Question

What is the escape speed from a planet with mass 1.2×1024kg and radius 3×106m? (G\=6.67×10−11N m2/kg2)

Options

Choose one · Correct answer highlighted

Explanation

ve = 2GMR. ve = 2×6.67×10−11×1.2×10243×106. ve = 5.336×107≈7.3×103m/s = 7.3km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 7.3 km/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

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