Practice question
Question
A solution of NaCl (molar mass = 58.5 g/mol) in 500 g of water freezes at -1.116°C. If Kf = 1.86 K kg mol⁻¹ , what is the mass of NaCl? (Assume complete dissociation, i = 2)
Explanation
Δ Tf = i · Kf · m . 1.116 = 2 × 1.86 × (moles/0.5) . 1.116 = 3.72 × (moles/0.5) , moles = (1.116 × 0.5/3.72) ≈ 0.15 . Mass = 0.15 × 58.5 = 8.775 g .
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