Practice question
Question
A solution is prepared by mixing 20 g of a solute (molar mass = 40 g/mol) with 80 g of water. What is the mole fraction of the solute?
Explanation
Moles of solute = (20/40) = 0.5 mol . Moles of water = (80/18) ≈ 4.444 mol . Total moles = 0.5 + 4.444 = 4.944. Mole fraction of solute = (0.5/4.944) ≈ 0.101 .
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