Practice question
Question
A solution of a non-volatile solute in water boils at 100.78°C at 1 atm. If 10 g of the solute (molar mass = 50 g/mol) was used in 500 g of water, what is the van’t Hoff factor? ( Kb = 0.52 K kg mol⁻¹ )
Explanation
Δ Tb = i · Kb · m . Moles = (10/50) = 0.2 , molality = (0.2/0.5) = 0.4 mol/kg . 0.78 = i × 0.52 × 0.4 . i = (0.78/0.52 × 0.4) ≈ 3.75 .
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