Practice question
Question
A solution is made by dissolving 12 g of a solute in water to make 300 mL of solution. If the osmotic pressure is 0.984 atm at 27°C, what is the molar mass of the solute? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
Pi = (w/M V) RT . 0.984 = (12/M × 0.3) × 0.0821 × 300 . M = (12 × 0.0821 × 300/0.984 × 0.3) ≈ 100 g/mol .
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