A weak acid HX has Ka = 2.5 × 10⁻⁶ . What is the pH of a solution made by mixing 0.1 M HX and 0.05 M NaX ?
Using Henderson-Hasselbalch: pH = pKa + log ([X-]/[HX]) , pKa = -log(2.5 × 10⁻⁶) ≈ 5.6 , ([X-]/[HX]) = (0.05/0.1) = 0.5 , pH = 5.6 + log 0.5 = 5.6 - 0.301 = 5.3 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Acid-Base Theories - Arrhenius Bronsted-Lowry Lewis and Salts Hydrolysis