Practice question
Question
What is the emf of the cell Sn(s) | Sn²⁺(0.05 M) || H⁺(0.1 M) | H₂(g)(1 bar) | Pt(s) at 298 K? (Given: E°Sn²⁺/Sn = -0.14 V , E°H⁺/H_₂ = 0.00 V )
Explanation
E°cell = 0.00 - (-0.14) = 0.14 V . Ecell = 0.14 - (0.059/2) log (0.05/0.1²) = 0.14 + 0.039 = 0.179 V .
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