Practice question
Question
The solubility of a gas in a solvent follows Henry’s law with a constant of 180 bar. If the partial pressure is increased by 50% from 6 bar, what is the new mole fraction of the gas?
Explanation
Initial p = 6 bar , new p = 6 × 1.5 = 9 bar . p = KH · x . New x = (9/180) = 0.05 .
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