Practice question
Question
A mixture of ethanol (molar mass = 46 g/mol) and water has a total mass of 138 g. If the mole fraction of ethanol is 0.25, what is the mass of ethanol in the mixture?
Explanation
Moles of ethanol = ne , moles of water = nw , total moles = ne + nw . (ne/ne + nw) = 0.25 . Mass: 46 ne + 18 nw = 138 . From mole fraction: nw = 3 ne . 46 ne + 18 (3 ne) = 138 , 46 ne + 54 ne = 138 , 100 ne = 138 , ne = 1.38 . Mass of ethanol = 1.38 × 46 = 63.48 g .
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