Practice question
Question
The Ksp of CaCO₃ is 3.8 × 10⁻⁹ . What is its solubility in pure water in mol/L?
Explanation
For CaCO₃ <=> Ca²⁺ + CO₃²⁻ , Ksp = [Ca²⁺][CO₃²⁻] = S² = 3.8 × 10⁻⁹ , S = sqrt3.8 × 10⁻⁹ ≈ 6.16 × 10⁻⁵ .
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