Practice question
Question
How many grams of Na₂SO₄ are produced when 14.2 g of NaOH reacts with excess H₂SO₄? (Molar masses: NaOH = 40 g/mol, Na₂SO₄ = 142 g/mol)
Explanation
Reaction: 2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O. Moles of NaOH = 14.2 / 40 = 0.355 mol. 2 mol NaOH produce 1 mol Na₂SO₄; 0.355 mol produce 0.1775 mol. Mass = 0.1775 × 142 ≈ 25.2 g.
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