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Question

How many grams of Ca(OH)₂ are required to produce 11.1 g of CaCl₂ with excess HCl? (Molar masses: Ca(OH)₂ = 74 g/mol, CaCl₂ = 111 g/mol)

Options

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Explanation

Reaction: Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O. Moles of CaCl₂ = 11.1/111 = 0.1 mol. 1 mol CaCl₂ from 1 mol Ca(OH)₂; mass = 0.1 × 74 = 7.4 g.