Practice question
Question
How many Faradays are required to deposit 5.85 g of sodium from NaNO₃ solution? (Atomic mass of Na = 23 g/mol)
Explanation
Na⁺ + e⁻ → Na . 1 mol Na (23 g) requires 1F. Moles = (5.85/23) = 0.2543 mol , Charge = 0.2543 × 1 = 0.2543 F .
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