Practice question
Question
How many Faradays are required to deposit 27 g of aluminum from molten Al₂O₃? (Atomic mass of Al = 27 g/mol)
Explanation
Al³⁺ + 3e⁻ → Al . 1 mol Al (27 g) requires 3F. Moles = (27/27) = 1 mol , Charge = 1 × 3 = 3F .
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