Practice question
Question
How many coulombs are required to deposit 0.965 g of barium from a BaCl₂ solution? (Atomic mass of Ba = 137 g/mol, F = 96500 C/mol)
Explanation
Ba²⁺ + 2e⁻ → Ba . 1 mol Ba (137 g) requires 2F. Moles = (0.965/137) = 0.00704 mol , Charge = 0.00704 × 2 × 96500 = 1358.24 C .
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