Practice question
Question
For XY₂(s) <=> X²⁺(aq) + 2Y-(aq) , if Ksp = 2.7 × 10⁻⁷ , what is the solubility of XY₂ in mol/L?
Explanation
Ksp = [X²⁺][Y-]² = S (2S)² = 4S³ = 2.7 × 10⁻⁷ , S³ = (2.7 × 10⁻⁷/4) = 6.75 × 10⁻⁸ , S ≈ 4.07 × 10⁻³ .
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