Skip to content
New summer mock series is live Attempt timed papers for SSC, banking, and engineering entrances with updated syllabi for this season. View exams
Login Register

Practice question

MCQ

Question

For the process CO(g) + 2H₂(g) → CH₃OH(l) , Δ H = -128 kJ/mol at 298 K, calculate Δ U . ( R = 8.314 J/mol·K )

Options

Choose one · Correct answer highlighted

Explanation

For CO(g) + 2H₂(g) → CH₃OH(l) , Δ ng = 0 - (1 + 2) = -3 . Then, RT = 8.314 × 298 × 10⁻³ = 2.4776 kJ . Using Δ H = Δ U + Δ ng RT , we get Δ U = Δ H - Δ ng RT = -128 - (-3 × 2.4776) = -128 + 7.4328 = -120.57 kJ/mol .

Related blogs

Guides and insights connected to this topic