Practice question
Question
For a reaction with Δ G° = -25.7 kJ/mol at 298 K, calculate K. (R = 8.314 J/mol·K)
Explanation
Δ G° = -RT ln K, -25.7 × 10³ = -8.314 × 298 × ln K, ln K = 10.37, K = e¹⁰.³⁷ ≈ 31800.
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