Practice question
Question
During electrolysis of aqueous K₂SO₄ with inert electrodes, 0.336 L of gas (STP) is collected at both electrodes. How many coulombs were passed? (F = 96500 C/mol)
Explanation
Cathode: 2H₂O + 2e⁻ → H₂ + 2OH⁻ , Anode: 2H₂O → O₂ + 4H⁺ + 4e⁻ . Total moles = (0.336/22.4) = 0.015 mol (H₂:O₂ = 2:1), H₂ = 0.01 mol, O₂ = 0.005 mol. Charge = (0.01 × 2 + 0.005 × 4) × 96500 = 0.04 × 96500 = 3860 C .
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