Practice question
Question
Calculate Δ Ssurr when 3 mol of a liquid freezes at 250 K if Δ Hfus = 5.5 kJ/mol.
Explanation
For freezing, Δ H = -n × Δ Hfus = -3 × 5.5 = -16.5 kJ, Δ Ssurr = -Δ H / T = -(-16.5 × 10³) / 250 = 66 J/K.
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