Practice question
Question
For a reaction with Δ H = 90 kJ/mol and Δ G = 30 kJ/mol at 300 K, what is Δ S?
Explanation
Δ G = Δ H - TΔ S, 30 = 90 - 300 Δ S, Δ S = (90 - 30) / 300 = 60 / 300 = 0.2 kJ/K = 200 J/K.
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