Practice question
Question
Calculate Δ H for CH₄(g) → C(g) + 4H(g) using: Δ Hf° (CH₄,g) = -74.8 kJ/mol, Δ Ha (C,g) = 715 kJ/mol, Δ Ha (H,g) = 218 kJ/mol.
Explanation
Δ H = [Δ Hf° (C) + 4 × Δ Hf° (H)] - Δ Hf° (CH₄) = [715 + 4 × 218] - (-74.8) = 715 + 872 + 74.8 = 1661.8 kJ/mol.
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