Practice question
Question
Calculate Δ H for 2C(s) + 3H₂(g) → C₂H₆(g) if Δ Hf° (C₂H₆,g) = -84.7 kJ/mol.
Explanation
Δ H = Δ Hf° (C₂H₆) - [2 × Δ Hf° (C) + 3 × Δ Hf° (H₂)] = -84.7 - [0 + 0] = -84.7 kJ/mol.
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