Practice question
Question
A weak acid HA ( Ka = 1.0 × 10⁻⁵ ) is 2% ionized in a solution. What is the concentration of HA ?
Explanation
Let [HA] = C , degree of ionization α = 0.02 , [H+] = C α = 0.02C . Ka = ([H+][A-]/[HA]) = ((0.02C)²/C(1 - 0.02)) ≈ (0.0004C²/0.98C) = 4.08 × 10⁻⁴C = 1.0 × 10⁻⁵ . Solving, C = (1.0 × 10⁻⁵/4.08 × 10⁻⁴) ≈ 0.0245 M .
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