Practice question
Question
A system absorbs 1500 J of heat and expands by 0.6 L against 3 atm at constant pressure. What is Δ U ? (1 atm·L = 101.325 J)
Explanation
Work done: w = -PΔ V = -3 × 0.6 × 101.325 = -181.985 J . Heat absorbed: q = 1500 J . Using the first law, Δ U = q + w = 1500 - 181.985 = 1318.0 J .
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