Practice question
Question
A solution of two volatile liquids with vapor pressures 300 mm Hg and 500 mm Hg has a total vapor pressure of 380 mm Hg. What is the mole fraction of the second component in the vapor phase?
Explanation
Liquid phase: 380 = 300 x₁ + 500 (1 - x₁) . 380 = 300 x₁ + 500 - 500 x₁ , 200 x₁ = 120 , x₁ = 0.6 , x₂ = 0.4 . Vapor phase: y₂ = (P₂⁰ · x₂/Ptotal) = (500 × 0.4/380) ≈ 0.5263 .
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