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Question

A solution of two volatile liquids has vapor pressures of 180 mm Hg and 240 mm Hg for pure components. If the total vapor pressure is 216 mm Hg, what is the mole fraction of the second component?

Options

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Explanation

P = P₁⁰ · x₁ + P₂⁰ · x₂ , where x₁ + x₂ = 1 . 216 = 180 (1 - x₂) + 240 x₂ . 216 = 180 - 180 x₂ + 240 x₂ . 216 - 180 = 60 x₂ , x₂ = (36/60) = 0.6 .