Practice question
Question
A solution of two volatile liquids has vapor pressures of 200 mm Hg and 300 mm Hg for pure components. If the total vapor pressure is 260 mm Hg, what is the mole fraction of the first component?
Explanation
P = P₁⁰ · x₁ + P₂⁰ · (1 - x₁) . 260 = 200 x₁ + 300 (1 - x₁) . 260 = 200 x₁ + 300 - 300 x₁ . 260 - 300 = -100 x₁ , x₁ = 0.4 .
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