Practice question
Question
A solution of two volatile liquids has vapor pressures of 150 mm Hg and 250 mm Hg for pure components. If the total vapor pressure is 190 mm Hg, what is the mole fraction of the first component?
Explanation
P = P₁⁰ · x₁ + P₂⁰ · (1 - x₁) . 190 = 150 x₁ + 250 (1 - x₁) . 190 = 150 x₁ + 250 - 250 x₁ . 190 - 250 = -100 x₁ , x₁ = 0.6 .
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