Practice question
Question
A cell Zn(s) | Zn²⁺(0.001 M) || Br₂(l) | Br⁻(0.002 M) | Pt(s) operates at 298 K. What is the cell potential? (Given: E°Zn²⁺/Zn = -0.76 V , E°Br_₂/Br⁻ = 1.07 V )
Explanation
E°cell = 1.07 - (-0.76) = 1.83 V . Ecell = 1.83 - (0.059/2) log ([Zn²⁺][Br⁻]²/1) = 1.83 - 0.0295 log (0.001 × 0.000004) = 1.83 + 0.148 = 1.978 V .
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