Practice question
Question
A 0.15 molal solution of CaCl₂ in water has a freezing point depression of 0.837°C. What is the van’t Hoff factor? ( Kf = 1.86 K kg mol⁻¹ )
Explanation
Δ Tf = i · Kf · m . 0.837 = i × 1.86 × 0.15 . i = (0.837/1.86 × 0.15) ≈ 3 .
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