Practice question
Question
The Ksp of CaF₂ is 3.9 × 10⁻¹¹ . What is [Ca²⁺] in a saturated solution with 0.02 M NaF ?
Explanation
For CaF₂ <=> Ca²⁺ + 2F- , Ksp = [Ca²⁺][F-]² = 3.9 × 10⁻¹¹ . [F-] = 0.02 + 2[Ca²⁺] ≈ 0.02 , [Ca²⁺] (0.02)² = 3.9 × 10⁻¹¹ , [Ca²⁺] = 9.75 × 10⁻⁸ M .
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