Practice question
Question
The bond order of NO⁺ ion, considering its molecular orbital configuration, is:
Explanation
For NO⁺ (14 electrons - 1 = 13): (sigma 1s)² (sigma^* 1s)² (sigma 2s)² (sigma^* 2s)² (pi 2px)² (pi 2py)² (sigma 2pz)² . Bonding = 10, antibonding = 4. Bond order = (10 - 4/2) = 3 .
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