Practice question
Question
In 2Na₂S₂O₃ + I₂ → Na₂S₄O₆ + 2NaI, which element undergoes oxidation?
Explanation
S (+2 avg. in S₂O₃²⁻) becomes +2.5 avg. in S₄O₆²⁻, losing electrons; I (0 to -1) is reduced.
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