Practice question
Question
In 2MnO₂ + 4NaOH + O₂ → 2Na₂MnO₄ + 2H₂O, what is the total number of electrons transferred per mole of MnO₂?
Explanation
Mn (+4 in MnO₂) to +6 in Na₂MnO₄: 2 Mn atoms lose 2 × (6 - 4) = 4 electrons total. Per MnO₂ = 4/2 = 2.