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Question

In 2Cr(OH)3 + 3H₂O₂ + 4NaOH → 2Na₂CrO₄ + 8H₂O, how many electrons are lost per chromium atom?

Options

Choose one · Correct answer highlighted

Explanation

Cr (+3 in Cr(OH)3) to +6 in CrO₄²−: change = +6 - (+3) = +3; each Cr loses 3 electrons.